Question

Calculate the lattice energy of potassium chloride (KCl) using Born-Haber cycle, given the following information:- Ionization energy of potassium (K) = 419 kJ/mol- Electron affinity of chlorine (Cl) = -348 kJ/mol- Heat of sublimation of potassium (K) = 89 kJ/mol- Enthalpy of formation of potassium chloride (KCl) = -436 kJ/mol

Answer 1

To calculate the lattice energy of potassium chloride  KCl  using the Born-Haber cycle, we need to consider the following steps:1. Sublimation of potassium  K : H_sub = 89 kJ/mol2. Ionization of potassium  K : H_ion = 419 kJ/mol3. Electron affinity of chlorine  Cl : H_ea = -348 kJ/mol4. Formation of potassium chloride  KCl : H_f = -436 kJ/mol5. Lattice energy of potassium chloride  KCl : H_latticeThe Born-Haber cycle equation is:H_f = H_sub + H_ion + H_ea + H_latticeNow we can plug in the given values and solve for the lattice energy:-436 kJ/mol = 89 kJ/mol + 419 kJ/mol - 348 kJ/mol + H_latticeRearrange the equation to solve for H_lattice:H_lattice = -436 kJ/mol - 89 kJ/mol - 419 kJ/mol + 348 kJ/molH_lattice = -596 kJ/molSo, the lattice energy of potassium chloride  KCl  is -596 kJ/mol.