To calculate the heat of neutralization, we first need to determine the amount of heat released during the reaction. We can do this using the formula:q = mcTwhere q is the heat released, m is the mass of the solution, c is the specific heat capacity, and T is the temperature change.First, we need to find the mass of the solution. Since the density of water is approximately 1 g/mL, we can assume that the mass of the solution is equal to the combined volume of the hydrochloric acid and sodium hydroxide solutions:mass = volume of HCl + volume of NaOH = 50 mL + 50 mL = 100 mL = 100 gNow we can calculate the heat released:q = 100 g 4.18 J/gC 10C = 4180 JNext, we need to determine the moles of the limiting reactant. In this case, both the hydrochloric acid and sodium hydroxide have the same concentration and volume, so they will react in a 1:1 ratio:moles of HCl = 2.0 mol/L 0.050 L = 0.1 molmoles of NaOH = 2.0 mol/L 0.050 L = 0.1 molSince both reactants have the same number of moles, either one can be considered the limiting reactant. We'll use HCl as the limiting reactant for this calculation.Finally, we can calculate the heat of neutralization, which is the heat released per mole of limiting reactant:heat of neutralization = q / moles of limiting reactant = 4180 J / 0.1 mol = 41800 J/molThe heat of neutralization for this reaction is 41800 J/mol.