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Calculate the heat of hydration of magnesium sulfate. When 5.00 g of MgSO₄ is mixed with 25.0 mL of water at 25°C, the temperature of the resulting solution rises to 36.5°C. The specific heat of water is 4.18 J/(g•°C), and the density of the resulting solution is 1.03 g/mL.

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To calculate the heat of hydration of magnesium sulfate, we first need to determine the heat absorbed by the solution. We can do this using the formula:q = mcTwhere q is the heat absorbed, m is the mass of the solution, c is the specific heat of water, and T is the change in temperature.First, let's find the mass of the solution. Since the density of the solution is 1.03 g/mL, and the volume of the solution is 25.0 mL, we can calculate the mass as follows:mass = density  volumemass = 1.03 g/mL  25.0 mLmass = 25.75 gNow, we can calculate the change in temperature  T :T = T_final - T_initialT = 36.5C - 25CT = 11.5CNow we can calculate the heat absorbed by the solution  q :q = mcTq =  25.75 g  4.18 J/ gC   11.5C q = 1246.8 JNow, to find the heat of hydration per mole of magnesium sulfate, we need to divide the heat absorbed by the moles of MgSO. First, let's find the molar mass of MgSO:MgSO = 24.31 g/mol  Mg  + 32.07 g/mol  S  + 4 16.00 g/mol   O MgSO = 120.38 g/molNow, let's find the moles of MgSO:moles = mass / molar massmoles = 5.00 g / 120.38 g/molmoles = 0.0415 molFinally, we can calculate the heat of hydration of magnesium sulfate:Heat of hydration = q / molesHeat of hydration = 1246.8 J / 0.0415 molHeat of hydration = 30024 J/molTherefore, the heat of hydration of magnesium sulfate is approximately 30,024 J/mol.

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