To calculate the heat absorbed or released during the crystallization of sodium acetate, we need to determine the number of moles of sodium acetate and then multiply it by the enthalpy change of the process.First, let's find the molar mass of sodium acetate NaC2H3O2 :Na = 22.99 g/molC = 12.01 g/molH = 1.01 g/molO = 16.00 g/molMolar mass of sodium acetate = 1 22.99 + 2 12.01 + 3 1.01 + 2 16.00 = 22.99 + 24.02 + 3.03 + 32.00 = 82.04 g/molNow, let's find the number of moles of sodium acetate in 50g:moles = mass / molar mass = 50g / 82.04 g/mol = 0.609 molesNow, we can calculate the heat absorbed or released during the crystallization:q = moles enthalpy change = 0.609 moles -3.9 kJ/mol = -2.375 kJSince the enthalpy change is negative, the heat is released during the crystallization process. Therefore, 2.375 kJ of heat is released during the crystallization of 50g of sodium acetate from a solution.