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Calculate the exchange current density for a redox reaction where the standard potential is 0.7 V, and the transfer coefficient is 0.5, given that the rate constant for the reaction is 5 × 10^-7 mol/cm^2*s.

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To calculate the exchange current density  i0  for a redox reaction, we can use the following equation:i0 = n * F * k0 * Cwhere:- n is the number of electrons transferred in the redox reaction  assumed to be 1 if not specified - F is the Faraday constant  96,485 C/mol - k0 is the rate constant for the reaction  5  10^-7 mol/cm^2*s - C is the concentration of the reactants  assumed to be 1 mol/cm^3 if not specified In this case, we are given the standard potential  0.7 V  and the transfer coefficient  0.5 , but these values are not needed to calculate the exchange current density directly. Instead, they can be used to calculate the rate constant  k0  if it was not provided.Since we already have the rate constant  k0 , we can calculate the exchange current density directly using the equation:i0 = n * F * k0 * CAssuming n = 1 and C = 1 mol/cm^3:i0 = 1 * 96,485 C/mol *  5  10^-7 mol/cm^2*s  * 1 mol/cm^3i0 = 96,485 C/mol * 5  10^-7 mol/cm^2*si0 = 48.2425  10^-7 C/cm^2*sSo, the exchange current density for this redox reaction is approximately 48.2425  10^-7 C/cm^2*s or 4.82425  10^-5 A/cm^2.

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