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Calculate the enthalpy of polymerization for the formation of polyethylene from its monomer, ethylene, given the following information:- The enthalpy of formation for ethylene is -84.7 kJ/mol.- The enthalpy of combustion for ethylene is -1410.1 kJ/mol.- The enthalpy of combustion for polyethylene is -5115.0 kJ/mol.- The molar mass of ethylene i

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To calculate the enthalpy of polymerization, we will use the following equation:H_polymerization = H_combustion_polyethylene - n * H_combustion_ethylene + n * H_formation_ethylenewhere n is the number of ethylene molecules involved in the formation of one polyethylene molecule.Since the average degree of polymerization is 1000, it means that 1000 ethylene molecules are involved in the formation of one polyethylene molecule. Therefore, n = 1000.Now, we can plug in the given values:H_polymerization =  -5115.0 kJ/mol  - 1000 *  -1410.1 kJ/mol  + 1000 *  -84.7 kJ/mol H_polymerization = -5115.0 kJ/mol + 1410100 kJ/mol - 84700 kJ/molH_polymerization = 1324285 kJ/molHowever, this value is for the formation of one polyethylene molecule with a molar mass of 28,000 g/mol. To find the enthalpy of polymerization per mole of ethylene, we need to divide this value by the number of ethylene molecules involved  1000 :H_polymerization_per_mole_ethylene = 1324285 kJ/mol / 1000H_polymerization_per_mole_ethylene = 1324.285 kJ/molSo, the enthalpy of polymerization for the formation of polyethylene from its monomer, ethylene, is approximately 1324.3 kJ/mol.

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