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Calculate the enthalpy of formation of So₃(g) using the given thermochemical equations:2SO₂(g) + O₂(g) → 2SO₃(g)       ∆H = -197 kJ/mol2SO₂(g) + 2O₂(g) → 2SO₃(g)     ∆H = -792 kJ/mol

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To calculate the enthalpy of formation of SO g , we need to manipulate the given thermochemical equations to obtain the formation reaction of SO g  from its elements in their standard states. The formation reaction of SO g  is:S s  + 3/2 O g   SO g First, let's focus on the given equations:1  2SO g  + O g   2SO g        H = -197 kJ/mol2  2SO g  + 2O g   2SO g      H = -792 kJ/molWe can notice that equation 1  has the desired product  SO  and equation 2  has the desired reactants  S and O . We can manipulate these equations to obtain the formation reaction of SO g .First, divide equation 1  by 2:1/2  SO g  + 1/2 O g   SO g        H = -98.5 kJ/molNow, we need to obtain S s  from SO g . We can do this by subtracting equation 1/2  from equation 2 :2  2SO g  + 2O g   2SO g      H = -792 kJ/mol- 1/2  SO g  + 1/2 O g   SO g        H = +98.5 kJ/mol--------------------------------------------------------------Result: S s  + 3/2 O g   SO g        H = -693.5 kJ/molSo, the enthalpy of formation of SO g  is -693.5 kJ/mol.

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