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Calculate the enthalpy of adsorption of hydrogen gas on activated carbon if 2 grams of activated carbon absorb 0.025 moles of hydrogen gas at 298 K and the pressure of the system is 1 atm. The molar enthalpy of hydrogen gas is -285.8 kJ/mol at constant pressure.

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To calculate the enthalpy of adsorption of hydrogen gas on activated carbon, we can use the following equation:H_ads = H_gas - H_abswhere H_ads is the enthalpy of adsorption, H_gas is the molar enthalpy of hydrogen gas, and H_abs is the enthalpy of absorption.First, we need to calculate the enthalpy of absorption  H_abs . We can use the ideal gas law to find the work done by the gas during the absorption process:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.Rearranging the equation to solve for V:V = nRT / PPlugging in the values:V =  0.025 moles  *  8.314 J/molK  *  298 K  /  1 atm * 101.325 J/Latm V  0.0614 LNow, we can calculate the work done by the gas  W :W = -PVSince the gas is absorbed by the activated carbon, the final volume is 0, so V = -0.0614 L. Plugging in the values:W = - 1 atm * 101.325 J/Latm  *  -0.0614 L W  6.22 JNow, we can calculate the enthalpy of absorption  H_abs :H_abs = U + WSince the process is isothermal  constant temperature , the change in internal energy  U  is 0. Therefore:H_abs = 0 + 6.22 JH_abs  6.22 JNow, we can calculate the enthalpy of adsorption  H_ads :H_ads = H_gas - H_absThe molar enthalpy of hydrogen gas is given as -285.8 kJ/mol, so for 0.025 moles, it is:H_gas = -285.8 kJ/mol * 0.025 moles = -7.145 kJConverting H_abs to kJ:H_abs  6.22 J *  1 kJ / 1000 J  = 0.00622 kJNow, we can find H_ads:H_ads = -7.145 kJ - 0.00622 kJH_ads  -7.151 kJSo, the enthalpy of adsorption of hydrogen gas on activated carbon is approximately -7.151 kJ.

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