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Calculate the enthalpy change of polymerization for the formation of polystyrene from its monomer, styrene, given the following data:- ΔH°f (Styrene) = -25.68 kJ/mol- Bond enthalpies: C-C = 347 kJ/mol; C=C = 611 kJ/mol; C-H = 413 kJ/mol

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To calculate the enthalpy change of polymerization for the formation of polystyrene from its monomer, styrene, we need to consider the bonds broken and bonds formed during the process. In the polymerization process, the double bond  C=C  in styrene is broken and a single bond  C-C  is formed between the styrene monomers. 1. Bonds broken: One C=C bond in each styrene monomer2. Bonds formed: One C-C bond between each styrene monomerNow, we can calculate the enthalpy change for the polymerization process using the given bond enthalpies:H_polymerization =  Bonds formed - Bonds broken H_polymerization = [ 1  C-C  -  1  C=C ]Using the given bond enthalpies:H_polymerization = [ 1  347 kJ/mol  -  1  611 kJ/mol ]H_polymerization = -264 kJ/molSo, the enthalpy change of polymerization for the formation of polystyrene from its monomer, styrene, is -264 kJ/mol.

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