Question

Calculate the enthalpy change of isomerization for the reaction of cyclopropane to propene given that the standard enthalpy of formation of cyclopropane is -119.1 kJ/mol and the standard enthalpy of formation of propene is -103.8 kJ/mol. Assume that the enthalpy change of vaporization for both compounds is negligible.

Answer 1

To calculate the enthalpy change of isomerization for the reaction of cyclopropane to propene, we can use the following equation:H_reaction =  H_f products  -  H_f reactants In this case, the reactant is cyclopropane and the product is propene. The standard enthalpy of formation  H_f  for cyclopropane is -119.1 kJ/mol, and for propene, it is -103.8 kJ/mol.H_reaction = [ -103.8 kJ/mol  * 1] - [ -119.1 kJ/mol  * 1]H_reaction = -103.8 kJ/mol + 119.1 kJ/molH_reaction = 15.3 kJ/molThe enthalpy change of isomerization for the reaction of cyclopropane to propene is 15.3 kJ/mol.