Question

Calculate the enthalpy change of ionization for magnesium given the following data: Mg(g) → Mg+(g) + e- ΔH1 = +738 kJ/mol Mg+(g) → Mg2+(g) + e- ΔH2 = +1451 kJ/mol

Answer 1

To calculate the enthalpy change of ionization for magnesium, we need to consider both ionization steps:1. Mg g   Mg+ g  + e-  H1 = +738 kJ/mol 2. Mg+ g   Mg2+ g  + e-  H2 = +1451 kJ/mol The enthalpy change of ionization for magnesium can be calculated by adding the enthalpy changes for both steps:H_total = H1 + H2H_total =  +738 kJ/mol  +  +1451 kJ/mol H_total = +2189 kJ/molThe enthalpy change of ionization for magnesium is +2189 kJ/mol.