First, we need to determine the number of moles of ethane C2H6 in 5.00 g. The molar mass of ethane is:C2H6 = 2 12.01 g/mol for C + 6 1.01 g/mol for H = 24.02 + 6.06 = 30.08 g/molNow, we can find the number of moles of ethane:moles of C2H6 = mass of C2H6 / molar mass of C2H6 moles of C2H6 = 5.00 g / 30.08 g/mol = 0.166 molesNext, we can use the standard enthalpy of combustion of ethane -1560 kJ/mol to calculate the enthalpy change for the combustion of 0.166 moles of ethane:H_combustion = moles of C2H6 standard enthalpy of combustionH_combustion = 0.166 moles -1560 kJ/mol = -258.96 kJTherefore, the enthalpy change of combustion for 5.00 g of ethane is approximately -259 kJ.