Question

Calculate the enthalpy change for the hydrolysis of 2 moles of sucrose (C12H22O11) into glucose (C6H12O6) and fructose (C6H12O6) given the following information:- Enthalpy of formation of glucose = -1273 kJ/mol- Enthalpy of formation of fructose = -1260 kJ/mol- Enthalpy of formation of sucrose = -2226 kJ/mol

Answer 1

To calculate the enthalpy change for the hydrolysis of 2 moles of sucrose, we can use the following equation:H_reaction =  H_products -  H_reactantsFor this reaction, the reactants are 2 moles of sucrose and the products are 2 moles of glucose and 2 moles of fructose. Therefore, we can write the equation as:H_reaction =  2  H_glucose + 2  H_fructose  -  2  H_sucrose Now, we can plug in the given values for the enthalpy of formation of glucose, fructose, and sucrose:H_reaction =  2  -1273 kJ/mol + 2  -1260 kJ/mol  -  2  -2226 kJ/mol H_reaction =  -2546 kJ + -2520 kJ  -  -4452 kJ H_reaction = -5066 kJ + 4452 kJH_reaction = -614 kJSo, the enthalpy change for the hydrolysis of 2 moles of sucrose into glucose and fructose is -614 kJ.