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Calculate the enthalpy change for the hydrolysis of 0.025 moles of ethyl acetate (C4H8O2) in the presence of excess water, given that the enthalpy of reaction is -56.0 kJ/mol.

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To calculate the enthalpy change for the hydrolysis of 0.025 moles of ethyl acetate, we can use the following equation:H = moles  enthalpy of reactionH = 0.025 moles   -56.0 kJ/mol H = -1.4 kJThe enthalpy change for the hydrolysis of 0.025 moles of ethyl acetate is -1.4 kJ.

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