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Calculate the enthalpy change for the following reaction:2H2O2(aq) → 2H2O(l) + O2(g)Using the following information:2H2O(l) + 105.2 kJ → 2H2(g) + O2(g)2H2(g) + O2(g) → 2H2O2(aq) + 484.4 kJ

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To calculate the enthalpy change for the reaction 2H2O2 aq   2H2O l  + O2 g , we can use Hess's Law. Hess's Law states that the enthalpy change of a reaction is the same whether it occurs in one step or several steps. We can use the given reactions to create a pathway to the desired reaction.Given reactions:1  2H2O l  + 105.2 kJ  2H2 g  + O2 g 2  2H2 g  + O2 g   2H2O2 aq  + 484.4 kJWe want to find the enthalpy change for the reaction:3  2H2O2 aq   2H2O l  + O2 g First, we need to reverse reaction 1:1'  2H2 g  + O2 g   2H2O l  - 105.2 kJNow, we can add reaction 1' and reaction 2 to get the desired reaction:1'  2H2 g  + O2 g   2H2O l  - 105.2 kJ2  2H2 g  + O2 g   2H2O2 aq  + 484.4 kJ----------------------------------------------3  2H2O2 aq   2H2O l  + O2 g  +  484.4 - 105.2  kJThe enthalpy change for the desired reaction is:H = 484.4 kJ - 105.2 kJ = 379.2 kJ

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