0 votes
45 views
in Chemical thermodynamics by (650 points)
Calculate the enthalpy change for the combustion of methane gas (CH4) at constant pressure, given that the standard enthalpy of formation for CH4 is -74.8 kJ/mol and the balanced chemical equation for the combustion reaction is:CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l) The molar enthalpy of formation of

1 Answer

0 votes
by (390 points)
To calculate the enthalpy change for the combustion of methane gas  CH4  at constant pressure, we can use Hess's Law, which states that the enthalpy change for a reaction is the same whether it occurs in one step or several steps. We can use the standard enthalpies of formation for the reactants and products to determine the enthalpy change for the reaction.The balanced chemical equation for the combustion of methane is:CH4  g  + 2 O2  g   CO2  g  + 2 H2O  l The enthalpy change for the reaction  H  can be calculated using the following equation:H =  [Hf products ] -  [Hf reactants ]where Hf represents the standard enthalpy of formation.For the products:1 mol of CO2: -393.5 kJ/mol2 mol of H2O: 2 * -285.8 kJ/mol = -571.6 kJ/molFor the reactants:1 mol of CH4: -74.8 kJ/mol2 mol of O2: 2 * 0 kJ/mol = 0 kJ/mol  The standard enthalpy of formation for an element in its standard state is zero. Now, we can calculate the enthalpy change for the reaction:H = [ -393.5  +  -571.6 ] - [ -74.8  +  0 ]H =  -965.1  -  -74.8 H = -890.3 kJ/molThe enthalpy change for the combustion of methane gas  CH4  at constant pressure is -890.3 kJ/mol.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...