Question

Calculate the enthalpy change (in kJ/mol) for the isomerization reaction of butene-1 to butene-2. Given the standard enthalpy of formation values for butene-1 as -126.3 kJ/mol and butene-2 as -126.0 kJ/mol, and the heat of combustion values for butene-1 as -2670.0 kJ/mol and butene-2 as -2666.0 kJ/mol.

Answer 1

To calculate the enthalpy change  H  for the isomerization reaction of butene-1 to butene-2, we can use the following equation:H = H_f products  - H_f reactants where H_f is the standard enthalpy of formation.In this case, the reaction is:butene-1  butene-2So, the enthalpy change for the reaction is:H = H_f butene-2  - H_f butene-1 Given the standard enthalpy of formation values for butene-1 as -126.3 kJ/mol and butene-2 as -126.0 kJ/mol, we can plug these values into the equation:H =  -126.0 kJ/mol  -  -126.3 kJ/mol H = 0.3 kJ/molTherefore, the enthalpy change for the isomerization reaction of butene-1 to butene-2 is 0.3 kJ/mol.