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Calculate the corrosion rate of an iron rod with a surface area of 20 cm² that is connected to a copper plate with a surface area of 25 cm², immersed in a solution of 0.5 M copper sulfate, given that the measured current is 0.2 A.

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To calculate the corrosion rate of the iron rod, we need to determine the mass loss of iron due to the electrochemical reaction. The reaction taking place is:Fe  s   Fe  aq  + 2eThe current  I  is given as 0.2 A. We can use Faraday's law of electrolysis to determine the mass loss of iron:m =  I  t  M  /  n  F where:m = mass loss of iron  g I = current  A t = time  s M = molar mass of iron  g/mol n = number of electrons transferred in the reactionF = Faraday's constant  96485 C/mol We are given the current  I = 0.2 A  and the number of electrons transferred in the reaction  n = 2 . The molar mass of iron  M  is 55.85 g/mol. However, we need the time  t  to calculate the mass loss of iron.Since we are asked for the corrosion rate, we can express it as mass loss per unit time  g/s . Therefore, we can rewrite the equation as:corrosion rate =  I  M  /  n  F corrosion rate =  0.2 A  55.85 g/mol  /  2  96485 C/mol corrosion rate = 0.000577 g/sNow, we need to convert the corrosion rate from mass loss per unit time to a unit of length, such as mm/year. To do this, we need the density    of iron and the surface area  A  of the iron rod: = 7.87 g/cm  density of iron A = 20 cm  surface area of the iron rod We can use the following equation to convert the corrosion rate to mm/year:corrosion rate  mm/year  =  corrosion rate  g/s   10 mm/cm  1 year  /    g/cm   A  cm   3.1536  10 s/year corrosion rate  mm/year  =  0.000577 g/s  10 mm/cm  1 year  /  7.87 g/cm  20 cm  3.1536  10 s/year corrosion rate  mm/year   0.184 mm/yearThe corrosion rate of the iron rod is approximately 0.184 mm/year.

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