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Calculate the corrosion potential of a silver metal in a solution containing 0.1 M silver nitrate and 1 M nitric acid given that the standard reduction potential of the Ag⁺/Ag couple is +0.80 V and the standard reduction potential of the NO₃⁻/NO₂⁻ couple is +0.96 V.

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To calculate the corrosion potential of silver metal in the given solution, we need to consider the Nernst equation. The Nernst equation relates the reduction potential of an electrochemical reaction to the standard electrode potential, temperature, and the activities of the chemical species undergoing the redox reaction.The Nernst equation is given by:E = E -  RT/nF  * ln Q where E is the reduction potential, E is the standard reduction potential, R is the gas constant  8.314 J/molK , T is the temperature in Kelvin  assume 298 K , n is the number of electrons transferred in the redox reaction, F is the Faraday constant  96485 C/mol , and Q is the reaction quotient.For the Ag/Ag couple, the half-cell reaction is:Ag + e  AgThe standard reduction potential E Ag/Ag  is +0.80 V. The reaction quotient Q for this reaction is given by:Q Ag/Ag  = [Ag]/[Ag]Since the concentration of Ag ions in the solution is 0.1 M, we can write:Q Ag/Ag  = 1/0.1 = 10Now, we can calculate the reduction potential E Ag/Ag  using the Nernst equation:E Ag/Ag  = 0.80 V -  8.314 J/molK * 298 K /  1 * 96485 C/mol   * ln 10 E Ag/Ag  = 0.80 V -  0.0257 V  * ln 10 E Ag/Ag  = 0.80 V - 0.0592 VE Ag/Ag  = 0.7408 VFor the NO/NO couple, the half-cell reaction is:NO + 2H + e  NO + HOThe standard reduction potential E NO/NO  is +0.96 V. The reaction quotient Q for this reaction is given by:Q NO/NO  =  [NO] * [H]  / [NO]Since the concentration of NO ions in the solution is 1 M  from 1 M nitric acid  and the concentration of H ions is also 1 M  from the nitric acid , we can assume that the concentration of NO ions is negligible compared to the other ions. Therefore, we can write:Q NO/NO    0 * 1  / 1 = 0Now, we can calculate the reduction potential E NO/NO  using the Nernst equation:E NO/NO  = 0.96 V -  8.314 J/molK * 298 K /  1 * 96485 C/mol   * ln 0 However, the ln 0  term is undefined. In practice, this means that the reduction potential for the NO/NO couple will be very high and the reaction will not occur under these conditions. Therefore, the corrosion potential of silver metal in this solution will be dominated by the Ag/Ag couple.So, the corrosion potential of silver metal in the given solution is approximately 0.7408 V.

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