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Calculate the corrosion potential of a copper electrode immersed in a 1 M CuSO4 solution in contact with a silver electrode immersed in a 1 M AgNO3 solution. Given that the standard reduction potentials of Cu2+/Cu and Ag+/Ag are +0.34 V and +0.80 V, respectively. Determine which electrode will corrode and which electrode will act as a cathode in the

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To calculate the corrosion potential and determine which electrode will corrode and which will act as a cathode, we need to find the cell potential  E_cell  for the galvanic cell. The cell potential can be calculated using the standard reduction potentials of the two half-cells.E_cell = E_cathode - E_anodeSince we want the cell potential to be positive  spontaneous reaction , we need to choose the half-cell with the higher reduction potential as the cathode and the one with the lower reduction potential as the anode.In this case, the standard reduction potentials are:Cu2+/Cu: +0.34 VAg+/Ag: +0.80 VSince the reduction potential of Ag+/Ag is higher than that of Cu2+/Cu, the silver electrode will act as the cathode, and the copper electrode will act as the anode.Now, we can calculate the cell potential:E_cell = E_cathode - E_anodeE_cell =  +0.80 V  -  +0.34 V E_cell = +0.46 VThe corrosion potential of the copper electrode immersed in a 1 M CuSO4 solution in contact with a silver electrode immersed in a 1 M AgNO3 solution is +0.46 V. The copper electrode will corrode  act as the anode , and the silver electrode will act as the cathode.

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