To calculate the change in enthalpy H for the combustion of 10 grams of propane, we first need to determine the number of moles of propane involved in the reaction. The molecular weight of propane C3H8 is: 3 * 12.01 g/mol for C + 8 * 1.01 g/mol for H = 36.03 + 8.08 = 44.11 g/molNow, we can calculate the number of moles of propane:10 g / 44.11 g/mol = 0.2266 moles of propaneThe heat released by the reaction is given as -2202 kJ. Since the heat released is negative, this indicates that the reaction is exothermic. To find the change in enthalpy H per mole of propane, we can divide the total heat released by the number of moles of propane:H = -2202 kJ / 0.2266 moles = -9717.5 kJ/molTherefore, the change in enthalpy H for the combustion of 10 grams of propane is approximately -9717.5 kJ/mol.