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Calculate the cell potential for the following electrochemical reaction at 25°C: Zn(s) + 2AgNO3(aq) → Zn(NO3)2(aq) + 2Ag(s) Given: E°(Ag+/Ag) = +0.80 V E°(Zn2+/Zn) = −0.76 V

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To calculate the cell potential for the given electrochemical reaction, we can use the Nernst equation. However, since we are given standard reduction potentials and the temperature is 25C, we can simplify the calculation by using the following equation:E cell  = E cathode  - E anode First, we need to identify the cathode and anode half-reactions. The cathode is where reduction occurs, and the anode is where oxidation occurs. In this case:Oxidation  anode : Zn s   Zn aq  + 2e, E Zn/Zn  = 0.76 VReduction  cathode : 2Ag aq  + 2e  2Ag s , E Ag/Ag  = +0.80 VNow, we can plug these values into the equation:E cell  = E cathode  - E anode E cell  =  +0.80 V  -  0.76 V E cell  = 0.80 V + 0.76 VE cell  = 1.56 VThe cell potential for the given electrochemical reaction at 25C is 1.56 V.

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