To calculate the bond order, we need to consider the molecular orbital MO diagram of the oxygen molecule and its ions. The bond order is calculated as follows:Bond order = Number of electrons in bonding MOs - Number of electrons in antibonding MOs / 21. O2 molecule:Oxygen has 8 electrons, so O2 has 16 electrons. The MO configuration is:1s, *1s, 2s, *2s, 2pz, 2px, 2py, *2px, *2pyBond order of O2 = 10 - 6 / 2 = 22. O2+ ion:O2+ has 15 electrons. The MO configuration is:1s, *1s, 2s, *2s, 2pz, 2px, 2py, *2pxBond order of O2+ = 9 - 6 / 2 = 1.53. O2- ion:O2- has 17 electrons. The MO configuration is:1s, *1s, 2s, *2s, 2pz, 2px, 2py, *2px, *2pyBond order of O2- = 10 - 7 / 2 = 1.54. O22- ion:O22- has 18 electrons. The MO configuration is:1s, *1s, 2s, *2s, 2pz, 2px, 2py, *2px, *2pyBond order of O22- = 10 - 8 / 2 = 1So, the bond orders are as follows:O2: 2O2+: 1.5O2-: 1.5O22-: 1