To calculate the bond length between the fluorine and carbon atoms in a CF4 molecule, we can use the formula for the potential energy of a diatomic molecule, which is given by:V r = 1/2 * k * r - r0 ^2where V r is the potential energy, k is the force constant, r is the bond length, and r0 is the equilibrium bond length.We can find the potential energy by converting the bond energy from kJ/mol to J/molecule:Bond energy = 544 kJ/mol * 1000 J/1 kJ * 1 mol/6.022 x 10^23 molecules = 9.03 x 10^-19 J/moleculeNow, we can set the potential energy equal to the formula for the potential energy of a diatomic molecule:9.03 x 10^-19 J = 1/2 * 455 N/m * r - r0 ^2To solve for r0, we can first divide both sides by 1/2 * 455 N/m: 9.03 x 10^-19 J / [ 1/2 * 455 N/m] = r - r0 ^21.98 x 10^-20 m^2 = r - r0 ^2Now, take the square root of both sides:sqrt 1.98 x 10^-20 m^2 = r - r01.41 x 10^-10 m = r - r0Since r and r0 are very close in value, we can approximate the bond length as:Bond length 1.41 x 10^-10 mSo, the bond length between the fluorine and carbon atoms in a CF4 molecule is approximately 1.41 x 10^-10 meters or 141 pm picometers .