Question

Calculate the bond dissociation energy (in kJ/mol) of the H-Cl bond in HCl using the following data: the standard enthalpy of formation of HCl is -92.31 kJ/mol, the bond energy of H-H is 436 kJ/mol, and the bond energy of Cl-Cl is 240 kJ/mol.

Answer 1

To calculate the bond dissociation energy of the H-Cl bond in HCl, we can use the following equation:Hf HCl  = 1/2 *  Bond energy of H-H  + 1/2 *  Bond energy of Cl-Cl  - Bond energy of H-ClRearranging the equation to solve for the bond energy of H-Cl, we get:Bond energy of H-Cl = 1/2 *  Bond energy of H-H  + 1/2 *  Bond energy of Cl-Cl  - Hf HCl Now, we can plug in the given values:Bond energy of H-Cl = 1/2 *  436 kJ/mol  + 1/2 *  240 kJ/mol  -  -92.31 kJ/mol Bond energy of H-Cl = 218 kJ/mol + 120 kJ/mol + 92.31 kJ/molBond energy of H-Cl = 430.31 kJ/molSo, the bond dissociation energy of the H-Cl bond in HCl is approximately 430.31 kJ/mol.