To calculate the amount of heat required to sublimate 10 grams of dry ice, we need to determine the number of moles of carbon dioxide and then use the heat of sublimation to find the total heat required.First, we need to find the molar mass of carbon dioxide CO . The atomic masses of carbon C and oxygen O are approximately 12.01 g/mol and 16.00 g/mol, respectively.Molar mass of CO = 12.01 g/mol for C + 2 * 16.00 g/mol for O = 12.01 + 32.00 = 44.01 g/molNow, we can find the number of moles of CO in 10 grams of dry ice:moles of CO = mass of CO / molar mass of COmoles of CO = 10 g / 44.01 g/mol 0.227 molesNext, we will use the heat of sublimation 25.2 kJ/mol to calculate the amount of heat required to sublimate 0.227 moles of CO:Heat required = moles of CO * heat of sublimationHeat required = 0.227 moles * 25.2 kJ/mol 5.72 kJTherefore, approximately 5.72 kJ of heat is required to sublimate 10 grams of dry ice at a temperature of -78.5C.