To calculate the amount of heat required to polymerize 2 moles of styrene into polystyrene, we can use the following formula:Heat q = moles n enthalpy of polymerization H Given that the enthalpy of polymerization for styrene is -56 kJ/mol and the reaction is exothermic, the heat released during the polymerization of 1 mole of styrene is 56 kJ.Now, we can calculate the heat required to polymerize 2 moles of styrene:q = 2 moles -56 kJ/mol q = -112 kJSince the reaction is exothermic, the negative sign indicates that the heat is released during the polymerization process. Therefore, 112 kJ of heat is released when 2 moles of styrene are polymerized into polystyrene.