To calculate the amount of heat absorbed or released, we need to find the moles of NaCl and the temperature change of the water. Then, we can use the enthalpy of crystallization and the specific heat capacity of water to find the heat absorbed or released.1. Calculate the moles of NaCl:The molar mass of NaCl is 58.44 g/mol 22.99 g/mol for Na and 35.45 g/mol for Cl .50 g NaCl * 1 mol NaCl / 58.44 g NaCl = 0.856 moles NaCl2. Calculate the heat absorbed or released by NaCl:The enthalpy of crystallization of NaCl is -787 kJ/mol.0.856 moles NaCl * -787 kJ/mol = -674.012 kJSince the enthalpy of crystallization is negative, the process is exothermic, and heat is released when NaCl dissolves in water. To find the temperature change of the water, we need to convert the heat released to Joules.-674.012 kJ * 1000 J/1 kJ = -674012 J3. Calculate the temperature change of the water:The specific heat capacity of water is 4.18 J/gC.q = mcTwhere q is the heat absorbed or released, m is the mass of the water, c is the specific heat capacity, and T is the temperature change.-674012 J = 200 g 4.18 J/gC T T = -674012 J / 200 g * 4.18 J/gC T = -807.17CSince the initial temperature of the water was 25C, the final temperature of the water would be:25C - 807.17C = -782.17CHowever, this result is not physically possible, as the temperature cannot go below the freezing point of water 0C in this scenario. This indicates that the heat released by the dissolution of NaCl is not sufficient to cause such a drastic temperature change in the water. In reality, the temperature change would be much smaller, and the system would reach an equilibrium state. The calculation above serves to demonstrate the exothermic nature of the dissolution process and the potential heat released, but it does not accurately represent the final temperature of the solution.