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Calculate the amount of heat absorbed or released when 2.5 moles of sodium acetate (NaCH3COO) is crystallized from its solution at a constant temperature of 25°C. The heat of crystallization for sodium acetate is -427 kJ/mol.

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To calculate the amount of heat absorbed or released during the crystallization of sodium acetate, we can use the following formula:q = n * Hwhere q is the heat absorbed or released, n is the number of moles, and H is the heat of crystallization.Given:n = 2.5 molesH = -427 kJ/molNow, we can plug in the values into the formula:q =  2.5 moles  *  -427 kJ/mol q = -1067.5 kJSince the value of q is negative, it indicates that heat is released during the crystallization process. Therefore, 1067.5 kJ of heat is released when 2.5 moles of sodium acetate crystallize from its solution at 25C.

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