To calculate the total amount of heat absorbed by the water during the process of crystallization, we need to consider two steps: 1. Cooling the water from 70C to 0C2. Solidifying the water into ice at 0CStep 1: Cooling the water from 70C to 0CTo calculate the heat absorbed during this step, we can use the formula:q = mcTwhere q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and T is the change in temperature.The specific heat capacity of water is 4.18 J/gC, the mass of the water is 50 grams, and the change in temperature is 70C - 0C = 70C.q1 = 50 g 4.18 J/gC 70C = 14630 JStep 2: Solidifying the water into ice at 0CTo calculate the heat absorbed during this step, we can use the formula:q = mLwhere q is the heat absorbed, m is the mass of the water, and L is the heat of crystallization.The heat of crystallization is given as 333.55 J/g, and the mass of the water is 50 grams.q2 = 50 g 333.55 J/g = 16677.5 JNow, we can add the heat absorbed in both steps to find the total heat absorbed:Total heat absorbed = q1 + q2 = 14630 J + 16677.5 J = 31307.5 JSo, the total amount of heat absorbed by the 50 grams of water during the process of crystallization is 31,307.5 J.