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Calculate the activation energy of a reaction that has a rate constant of 8.23 x 10^-4 s^-1 at 300 K and a rate constant of 1.56 x 10^-2 s^-1 at 350 K.

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To calculate the activation energy  Ea  of a reaction, we can use the Arrhenius equation:k = A * e^-Ea / R * T where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant  8.314 J/mol*K , and T is the temperature in Kelvin.We have two sets of data: k1 = 8.23 x 10^-4 s^-1 at T1 = 300 K and k2 = 1.56 x 10^-2 s^-1 at T2 = 350 K. We can set up two equations using the Arrhenius equation:k1 = A * e^-Ea / R * T1 k2 = A * e^-Ea / R * T2 Now, we can divide the first equation by the second equation to eliminate the pre-exponential factor  A :k1 / k2 = e^-Ea / R * T1  / e^-Ea / R * T2 Simplify the equation: k1 / k2  = e^ -Ea / R  *  1/T1 - 1/T2  Take the natural logarithm of both sides:ln k1 / k2  =  -Ea / R  *  1/T1 - 1/T2 Now, we can solve for Ea:Ea = -R * ln k1 / k2  /  1/T1 - 1/T2 Plug in the given values:Ea = -8.314 J/mol*K * ln  8.23 x 10^-4 s^-1  /  1.56 x 10^-2 s^-1   /  1/300 K - 1/350 K Ea  49050 J/molThe activation energy of the reaction is approximately 49.05 kJ/mol.

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