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A zinc electrode is immersed in a 1.0 M ZnSO4 solution and connected to a platinum electrode that is immersed in a 1.0 M CuSO4 solution. If the measured potential difference of the cell is 1.10 V at 25 °C, what is the polarization of the cell?

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To determine the polarization of the cell, we first need to calculate the standard cell potential  E  for the given reaction. The overall reaction in this cell is:Zn s  + Cu aq   Zn aq  + Cu s The standard reduction potentials for the half-reactions are:Zn aq  + 2e  Zn s   E = -0.76 VCu aq  + 2e  Cu s   E = +0.34 VTo obtain the overall cell potential, we add the standard reduction potentials:E cell  = E cathode  - E anode  = 0.34 V -  -0.76 V  = 1.10 VNow that we have the standard cell potential, we can compare it to the measured cell potential to determine the polarization. The polarization  P  is the difference between the measured potential  E  and the standard potential  E :P = E - EIn this case, the measured potential difference is given as 1.10 V, which is equal to the standard cell potential:P = 1.10 V - 1.10 V = 0 VTherefore, the polarization of the cell is 0 V. This means that there is no overpotential or concentration polarization affecting the cell, and the cell is operating at its standard conditions.

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