To solve this problem, we can use the Henderson-Hasselbalch equation, which relates the pH, pKa, and the ratio of the concentrations of the conjugate base A- and the weak acid HA :pH = pKa + log [A-]/[HA] The pKa of acetic acid is 4.74. First, let's find the initial pH of the solution:Initial pH = 4.74 + log 0.05/0.1 Initial pH = 4.74 - 0.301Initial pH 4.44Now, we want to increase the pH by 0.5 units, so the new pH will be:New pH = 4.44 + 0.5New pH = 4.94Now, we can use the Henderson-Hasselbalch equation again to find the new concentration of acetate ion [A'-] :4.94 = 4.74 + log [A'-]/0.1 Rearrange the equation to solve for [A'-]:0.2 = log [A'-]/0.1 10^0.2 = [A'-]/0.11.585 = [A'-]/0.1Now, solve for [A'-]:[A'-] = 1.585 * 0.1[A'-] 0.1585 MSo, the new concentration of acetate ion necessary to increase the pH of the solution by 0.5 units is approximately 0.1585 M.