To calculate the mass of copper deposited on the cathode, we can use Faraday's law of electrolysis. The formula is:mass = current time molar mass / n Faraday constant where:- mass is the mass of copper deposited in grams - current is the electric current in amperes - time is the duration of electrolysis in seconds - molar mass is the molar mass of copper in grams per mole - n is the number of electrons transferred per copper ion in this case, it's 2 for Cu - Faraday constant is the charge per mole of electrons in coulombs per mole First, we need to convert the time from minutes to seconds:10 minutes 60 seconds/minute = 600 secondsNow, we can plug in the values into the formula:mass = 2.5 A 600 s 63.55 g/mol / 2 96,485 C/mol mass = 1500 C 63.55 g/mol / 192,970 C/mol mass 0.492 gSo, the mass of copper deposited on the cathode is approximately 0.492 grams.