To calculate the maximum electrical work that can be obtained from an electrochemical cell, we first need to determine the cell potential E_cell . The cell potential can be calculated using the standard reduction potentials of the two half-reactions involved. In this case, we have a standard hydrogen electrode SHE and a zinc electrode.The standard reduction potential for the SHE is given as -0.76 V, and for the zinc electrode, it is given as -0.46 V. Since zinc is being oxidized, we need to reverse the sign of its reduction potential to obtain its oxidation potential.Oxidation potential of zinc = +0.46 VNow, we can calculate the cell potential E_cell using the following formula:E_cell = Reduction potential of cathode - Oxidation potential of anodeSince the SHE has a more negative reduction potential, it will act as the anode oxidation half-cell , and the zinc electrode will act as the cathode reduction half-cell .E_cell = -0.46 V - -0.76 V = 0.30 VNow that we have the cell potential, we can calculate the maximum electrical work W_max using the following formula:W_max = -n * F * E_cellwhere n is the number of moles of electrons transferred, F is the Faraday constant 96,485 C/mol , and E_cell is the cell potential.Since 0.5 moles of zinc metal is oxidized, and the oxidation of one mole of zinc releases two moles of electrons Zn -> Zn + 2e , the number of moles of electrons transferred n is:n = 0.5 moles of Zn * 2 moles of e/mole of Zn = 1 mole of eNow we can calculate the maximum electrical work:W_max = -1 mol * 96,485 C/mol * 0.30 V = -28,945.5 JThe maximum electrical work that can be obtained from this electrochemical cell is -28,945.5 Joules. The negative sign indicates that the work is done by the system the electrochemical cell on the surroundings.