A student needs to calculate the current density (in A/m^2) in an electrochemical cell with a cross-sectional area of 0.01 m^2 and a current of 0.5 A passing through it. The half-cell reactions are as follows:Anode: Zn(s) -> Zn2+(aq) + 2e^-Cathode: Cu2+(aq) + 2e^- -> Cu(s)The concentrations of Zn2+ and Cu2+ ions in the solutions are 0.1 M and 0.01 M, respectively. The temperature of the cell is 298 K. Calculate the current density.

Question

A student needs to calculate the current density (in A/m^2) in an electrochemical cell with a cross-sectional area of 0.01 m^2 and a current of 0.5 A passing through it. The half-cell reactions are as follows:Anode: Zn(s) -> Zn2+(aq) + 2e^-Cathode: Cu2+(aq) + 2e^- -> Cu(s)The concentrations of Zn2+ and Cu2+ ions in the solutions are 0.1 M and 0.01 M, respectively. The temperature of the cell is 298 K. Calculate the current

Answer 1

To calculate the current density, we can use the formula:Current density  J  = Current  I  / Cross-sectional area  A Given the current  I  is 0.5 A and the cross-sectional area  A  is 0.01 m^2, we can plug these values into the formula:J = 0.5 A / 0.01 m^2J = 50 A/m^2The current density in the electrochemical cell is 50 A/m^2.