To determine the overpotential of the reaction, we first need to calculate the theoretical cell potential Ecell for the reaction. The cell potential can be calculated using the standard reduction potentials of the two half-reactions involved:Ecell = E cathode - E anode In this case, the reduction of Ag+ ions is the cathode half-reaction, and the oxidation of Cu to Cu2+ is the anode half-reaction. So, we can plug in the standard reduction potentials:Ecell = 0.80 V - 0.34 V = 0.46 VNow that we have the theoretical cell potential, we can calculate the overpotential by comparing it to the measured cell potential:Overpotential = Measured cell potential - Theoretical cell potentialOverpotential = 0.62 V - 0.46 V = 0.16 VThe overpotential of the reaction is 0.16 V.To determine if the reduction of Ag+ occurs spontaneously, we can look at the sign of the cell potential. If the cell potential is positive, the reaction is spontaneous; if it is negative, the reaction is non-spontaneous.In this case, the theoretical cell potential Ecell is 0.46 V, which is positive. Therefore, the reduction of Ag+ ions occurs spontaneously.