To determine the empirical formula of the compound, we need to find the mole ratio of potassium K to chlorine Cl .First, we need to find the moles of each element:1. Moles of potassium K :Potassium has a molar mass of 39.10 g/mol.Moles of K = mass of K / molar mass of KMoles of K = 37.43 g / 39.10 g/mol = 0.957 moles2. Moles of chlorine Cl :Chlorine has a molar mass of 35.45 g/mol.Moles of Cl = mass of Cl / molar mass of ClMoles of Cl = 37.12 g / 35.45 g/mol = 1.047 molesNow, we need to find the mole ratio of K to Cl:Mole ratio of K:Cl = moles of K / moles of ClMole ratio of K:Cl = 0.957 / 1.047 1:1Since the mole ratio is approximately 1:1, the empirical formula of the compound is KCl.To find the molecular formula, we need to determine the molar mass of the compound:Molar mass of KCl = molar mass of K + molar mass of ClMolar mass of KCl = 39.10 g/mol + 35.45 g/mol = 74.55 g/molSince the molar mass of the compound 74.55 g/mol is equal to the molar mass of the empirical formula KCl , the molecular formula is also KCl.