To determine the mass of sodium and chlorine needed to synthesize 29.0 g of NaCl, we will use the balanced chemical equation and stoichiometry.The balanced chemical equation for the formation of NaCl from its constituent elements is:2Na + Cl 2NaClFirst, we need to find the molar mass of NaCl, sodium Na , and chlorine Cl .Molar mass of Na = 22.99 g/molMolar mass of Cl = 2 * 35.45 g/mol = 70.90 g/molMolar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/molNow, we will determine the moles of NaCl needed to synthesize 29.0 g of NaCl.moles of NaCl = mass of NaCl / molar mass of NaClmoles of NaCl = 29.0 g / 58.44 g/mol = 0.496 molUsing the stoichiometry from the balanced chemical equation, we can determine the moles of sodium and chlorine needed.moles of Na = 2 * moles of NaCl = 2 * 0.496 mol = 0.992 molmoles of Cl = 0.5 * moles of NaCl = 0.5 * 0.496 mol = 0.248 molFinally, we will convert the moles of sodium and chlorine to mass.mass of Na = moles of Na * molar mass of Na = 0.992 mol * 22.99 g/mol = 22.8 gmass of Cl = moles of Cl * molar mass of Cl = 0.248 mol * 70.90 g/mol = 17.6 gTherefore, the student should start with 22.8 g of sodium and 17.6 g of chlorine to synthesize 29.0 g of NaCl.