Question

A chemistry student needs to calculate the density of a 25.0 mL sample of titanium (III) nitrate that has a mass of 34.6 g. The student needs to determine the density of the sample in g/mL, and also provide their answer in kg/m³.

Answer 1

To calculate the density of the titanium  III  nitrate sample, we can use the formula:Density = Mass / VolumeGiven the mass of the sample is 34.6 g and the volume is 25.0 mL, we can plug these values into the formula:Density = 34.6 g / 25.0 mL = 1.384 g/mLNow, we need to convert the density from g/mL to kg/m. To do this, we can use the following conversion factors:1 g = 0.001 kg1 mL = 0.000001 mSo, we can convert the density to kg/m:1.384 g/mL *  0.001 kg / 1 g  *  1 mL / 0.000001 m  = 1384 kg/mTherefore, the density of the titanium  III  nitrate sample is 1.384 g/mL or 1384 kg/m.