To determine the boiling point of the solution, we can use the formula for boiling point elevation:Tb = Kb * molality * iwhere Tb is the change in boiling point, Kb is the boiling point elevation constant for water 0.512C/m , molality is the molality of the solution, and i is the van't Hoff factor number of particles the solute dissociates into, which is 1 for glucose as it does not dissociate in water .First, we need to find the molality of the solution. Molality is defined as the number of moles of solute per kilogram of solvent. 1. Calculate the moles of glucose:Molar mass of glucose C6H12O6 = 6 * 12.01 + 12 * 1.01 + 6 * 16.00 = 72.06 + 12.12 + 96.00 = 180.18 g/molMoles of glucose = 30 g / 180.18 g/mol = 0.1666 mol2. Convert the mass of water to kilograms:100 g = 0.1 kg3. Calculate the molality of the solution:Molality = 0.1666 mol / 0.1 kg = 1.666 mol/kg4. Calculate the boiling point elevation:Tb = Kb * molality * iTb = 0.512C/m * 1.666 mol/kg * 1 = 0.853C5. Determine the boiling point of the solution:Boiling point of solution = boiling point of pure water + TbBoiling point of solution = 100C + 0.853C = 100.853CThe boiling point of the solution is approximately 100.853C.