A chemistry student is provided with a mixture of two chemicals, A and B, but the quantity of each chemical is unknown. The student uses mass balance calculations to determine the mass of each component in the mixture. Chemical A has a molecular weight of 100 g/mol, while chemical B has a molecular weight of 120 g/mol. If the mixture contains 10% more of chemical A by mass than chemical B, what is the mass of each component in the mixture?

Question

A chemistry student is provided with a mixture of two chemicals, A and B, but the quantity of each chemical is unknown. The student uses mass balance calculations to determine the mass of each component in the mixture. Chemical A has a molecular weight of 100 g/mol, while chemical B has a molecular weight of 120 g/mol. If the mixture contains 10% more of chemical A by mass

Answer 1

Let's denote the mass of chemical A as mA and the mass of chemical B as mB. According to the problem, the mass of chemical A is 10% more than the mass of chemical B. We can write this as:mA = 1.10 * mBNow, we need more information to solve this problem, such as the total mass of the mixture. Let's assume the total mass of the mixture is mT. Then we can write:mT = mA + mBWe can substitute the expression for mA from the first equation into the second equation:mT = 1.10 * mB + mBNow, we need the value of mT to solve for mB and subsequently mA.