A chemistry student is given the following information: A galvanic cell is set up consisting of a copper electrode in a copper (II) ion solution connected by a salt bridge to a silver electrode in a silver ion solution. The concentration of the copper (II) solution is 0.10 M and the concentration of the silver ion solution is 0.025 M. The measured potential of the cell is 0.66 V. Calculate the resistance of this electrochemical cell.

Question

A chemistry student is given the following information: A galvanic cell is set up consisting of a copper electrode in a copper (II) ion solution connected by a salt bridge to a silver electrode in a silver ion solution. The concentration of the copper (II) solution is 0.10 M and the concentration of the silver ion solution is 0.025 M. The measured potential of the ce

Answer 1

To calculate the resistance of the electrochemical cell, we need to determine the current flowing through the cell. However, the information provided is not sufficient to directly calculate the resistance. We can only calculate the cell potential using the Nernst equation.The Nernst equation is given by:E_cell = E_cell -  RT/nF  * ln Q Where:E_cell = cell potential  0.66 V E_cell = standard cell potentialR = gas constant  8.314 J/molK T = temperature  assuming 298 K n = number of electrons transferred  2 for Cu/Cu and Ag/Ag redox couples F = Faraday's constant  96485 C/mol Q = reaction quotientFirst, we need to find the standard cell potential  E_cell . The standard reduction potentials for the half-reactions are:Cu + 2e  Cu: E = +0.34 VAg + e  Ag: E = +0.80 VThe overall cell reaction is:Cu + 2Ag  Cu + 2AgThe standard cell potential is the difference between the reduction potentials:E_cell = E Ag/Ag  - E Cu/Cu  = 0.80 V - 0.34 V = 0.46 VNow, we can find the reaction quotient  Q  for the cell reaction:Q = [Cu]/[Ag]^2 =  0.10 M / 0.025 M ^2 = 160Now, we can use the Nernst equation to calculate the cell potential:0.66 V = 0.46 V -  8.314 J/molK * 298 K /  2 * 96485 C/mol   * ln 160 Solving for the cell potential, we get:0.66 V = 0.46 V - 0.0427 V * ln 160 However, this equation does not provide any information about the current or resistance of the electrochemical cell. To calculate the resistance, we would need additional information such as the current flowing through the cell or the power generated by the cell.