Question

A chemical reaction of N2O4(g) ⇌ 2NO2(g) is established in a closed vessel at a certain temperature. The initial concentration of N2O4 is 0.1M. At equilibrium, the concentration of NO2 is found to be 0.6M. Calculate the equilibrium concentration of N2O4.

Answer 1

To calculate the equilibrium concentration of N2O4, we can use an ICE  Initial, Change, Equilibrium  table. Initial concentrations:[N2O4] = 0.1 M[NO2] = 0 M  since the reaction has not started yet Change in concentrations:Since the reaction is N2O4  2NO2, for every mole of N2O4 that reacts, 2 moles of NO2 are produced. Let x be the change in concentration of N2O4. Then, the change in concentration of NO2 is 2x.Equilibrium concentrations:[N2O4] = 0.1 - x[NO2] = 0 + 2xAt equilibrium, we are given that the concentration of NO2 is 0.6 M. Therefore, we can set up the following equation:2x = 0.6Solving for x, we get:x = 0.3Now, we can find the equilibrium concentration of N2O4:[N2O4] = 0.1 - x[N2O4] = 0.1 - 0.3[N2O4] = -0.2 MHowever, a negative concentration is not possible. This indicates that there might be an error in the given information. Please double-check the given values and ensure they are correct.