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Determine the oxidation state of the transition metal in potassium manganate (VII) and explain how you arrived at your answer.

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Potassium manganate  VII  has the chemical formula KMnO. To determine the oxidation state of the transition metal  Mn  in this compound, we need to consider the oxidation states of the other elements and the overall charge of the compound.Potassium  K  is an alkali metal and has an oxidation state of +1. Oxygen  O  typically has an oxidation state of -2. Since there is only one potassium atom and four oxygen atoms in the compound, the total oxidation state contributed by these elements is: +1  + 4 -2  = +1 - 8 = -7The compound KMnO is neutral, meaning its overall charge is 0. Therefore, the oxidation state of manganese  Mn  must balance the -7 contributed by the potassium and oxygen atoms:Mn +  -7  = 0Solving for the oxidation state of Mn:Mn = +7So, the oxidation state of the transition metal manganese  Mn  in potassium manganate  VII  is +7.
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