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Consider the following equation: Fe + HCl --> FeCl3 + H2. If you have 10 grams of Fe and an excess of HCl, what mass of H2 will be produced?

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To solve this problem, we need to use stoichiometry. First, we need to balance the chemical equation:Fe + 6HCl --> FeCl3 + 3H2Now that the equation is balanced, we can proceed with the stoichiometry calculations.1. Determine the molar mass of Fe and H2.Fe: 55.85 g/molH2: 2.02 g/mol  1.01 g/mol for each H atom 2. Convert the mass of Fe to moles.10 g Fe *  1 mol Fe / 55.85 g Fe  = 0.179 moles Fe3. Use the stoichiometry from the balanced equation to determine the moles of H2 produced.0.179 moles Fe *  3 moles H2 / 1 mole Fe  = 0.536 moles H24. Convert the moles of H2 to grams.0.536 moles H2 *  2.02 g H2 / 1 mole H2  = 1.08 g H2So, 1.08 grams of H2 will be produced.

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