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What is the product(s) formed when 1-bromo-2-methylcyclohexane undergoes an E1 mechanism of elimination?

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When 1-bromo-2-methylcyclohexane undergoes an E1 mechanism of elimination, a carbocation is formed as an intermediate. The bromine atom leaves, creating a carbocation at the 1-position. Then, a hydrogen atom is removed from a neighboring carbon  either at the 3-position or the 6-position  by a base, leading to the formation of an alkene.There are two possible products formed in this reaction due to the two different positions where the hydrogen can be removed:1. If the hydrogen is removed from the 3-position, the product formed is 1-methylcyclohexene.2. If the hydrogen is removed from the 6-position, the product formed is 3-methylcyclohexene.Both products are formed as a mixture, with 1-methylcyclohexene being the major product due to the more stable trans-alkene configuration.
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