When 1-bromobutane is reacted with aqueous sodium hydroxide NaOH , the product formed is 1-butanol. This reaction is an example of a nucleophilic substitution reaction, specifically an SN2 reaction.Here is the mechanism for this reaction:1. The hydroxide ion OH- from sodium hydroxide acts as a nucleophile and attacks the electrophilic carbon atom the one bonded to the bromine in 1-bromobutane.2. As the hydroxide ion forms a bond with the carbon atom, the carbon-bromine bond starts to break, and the bromide ion Br- is released as a leaving group.3. The final product, 1-butanol, is formed as the hydroxide ion is now bonded to the carbon atom, and the bromide ion is released as a byproduct.The reaction can be represented as:CH3CH2CH2CH2Br + OH- CH3CH2CH2CH2OH + Br-