When 1-methylcyclohexene reacts with ethylene oxide in the presence of catalytic sulfuric acid, the major product formed is 1-methyl-2- 2-hydroxyethyl cyclohexanol. The reaction proceeds through the following steps:1. The sulfuric acid protonates the ethylene oxide, making it more electrophilic.2. The nucleophilic double bond of 1-methylcyclohexene attacks the electrophilic carbon of the protonated ethylene oxide, forming a new carbon-carbon bond.3. The positive charge on the oxygen is neutralized by deprotonation, leading to the formation of the alcohol group.The final product, 1-methyl-2- 2-hydroxyethyl cyclohexanol, is formed as a result of the nucleophilic addition of 1-methylcyclohexene to the protonated ethylene oxide followed by deprotonation.