The given compound is CH3CH2CH2OH, which can also be written as C3H7OH. This compound contains an -OH group, which is an alcohol functional group.When the alcohol reacts with sodium hydroxide NaOH , it will undergo a reaction called acid-base reaction. In this reaction, the acidic hydrogen atom from the alcohol -OH group will be replaced by a sodium ion Na+ , forming a sodium alkoxide salt and water as a byproduct.The reaction can be represented as follows:C3H7OH + NaOH C3H7ONa + H2OThe product formed is sodium propoxide C3H7ONa and water H2O .